Inverse of a matrix in ℤ/pℤ : Inverse

### 2.32.6 Inverse of a matrix in ℤ/pℤ : `Inverse`

`Inverse` is the inert form of `inverse`.
`Inverse` takes as argument a matrix with coefficients in ℤ/pℤ.
`Inverse` returns `inverse` without evaluation. It is used in conjonction with `mod` in Maple syntax mode to find the inverse of a matrix with coefficients in ℤ/pℤ.
Input in `Xcas` mode :

`Inverse([[1,2,9] mod 13,[3,10,0] mod 13,[3,11,1] mod13])`

Output :

`inverse([[1%13,2%13,9%13],[3%13,10%13,0%13], [3%13,11%13,1%13]])`

you need to `eval(ans())` to get :

`[[2%13,-4%13,-5%13],[2%13,0%13,-5%13], [-2%13,-1%13,6%13]]`

which is the inverse of A=[[1,2,9],[3,10,0],[3,11,1]] in ℤ/13ℤ.
Input in `Maple` mode :

`Inverse([[1,2,9],[3,10,0],[3,11,1]]) mod 13`

Output :

`[[2,-4,-5],[2,0,-5],[-2,-1,6]]`