Defining a function with history: as_function_of

### 5.16.6 Defining a function with history: as_function_of

The as_function_of command creates a function defined by an expression, even if the desired variable already has a value.

- as_function_of takes two arguments:
  - x, a variable.
  - exprvar, another variable containing an expression which itself may involve x.
- as_function_of(exprvar,x) returns a function defined by the expression that exprvar contains.

#### Example.

Input:

a:=sin(x)

Output:

sin | ⎛ ⎝ | x | ⎞ ⎠

Input:

b:=sqrt(1+a^2)

Output:

√ |
1+sin2x

Input:

c:=as_function_of(b,a)

Output:

(a) -> { return(sqrt(1+a^2));}

Input:

c(x)

Output:

√ |
1+x2

Warning !!
If the variable b has been assigned several times, the first assignment of b following the last assignment of a will be used. Moreover, the order used is the order of validation of the commandlines, which may not be reflected by the Xcas interface if you reused previous commandlines.

#### Example.

Input:

a:=2 b:=2*a+1 b:=3*a+2 c:=as_function_of(b,a)

Output:

(a) -> {return(2*a+1);}

So c(x) is equal to 2*x+1. But: Input:

a:=2
b:=2*a+1
a:=2
b:=3*a+2
c:=as_function_of(b,a)

Output:

(a) -> {return(3*a+2);}

So c(x) is equal to 3*x+2.
Hence the line where a is defined must be reevaluated before the good definition of b.